Answer to Question #311735 in Mechanics | Relativity for Eunice

Question

Leo who has a mass of 70 kg stretches

the trampoline mat by 37 cm. Calculate the

elastic potential energy he puts into the

trampoline mat.

Answer 1

Answer

Spring constant

$K=\frac{mg}{x}\\=\frac{70*9.81}{0.37}\\=1.85*10^3N/m$

So

elastic potential energy

$U=\frac{kx^2}{2}\\=\frac{1.85*10^30.37*0.37}{2}\\=127.04J$