A positive 6.0x10^-9 C charge experiences a force of 1.8c10^-5 N to the right. What is the electric field at the location of that charge from other charges?
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Expert's answer
2011-02-18T06:30:08-0500
The electric field is E = F/q = 1.8x10-5[N]/6.9x10-9 [C]= 2608.7 [V/m].
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