Answer to Question #348264 in Electric Circuits for Rahul

Question #348264

Two identical light bulb, each with resistance R = 2􀀺 are connected to a source with E = 8

V and negligible internal resistance. Find the current through each bulb. The potential

difference across each bulb and the power delivered to each bulb and to the entire network

if the bulbs are connected parallel


1
Expert's answer
2022-06-06T17:01:09-0400

Given:

"E=8V; R=2\\Omega;"

Find:

"I1" - current though 1st bulb;

"I2" - current though 2nd bulb;

"U1" - potential difference across 1st bulb;

"U2" - potential difference across 2nd bulb;

"P1" - power delivered to 1st bulb;

"P2" - power delivered to 2nd bulb;

"P" - total power delivered to system.

Solution:

Let's find total resistance and current.

The bulbs connected parallel, so

"Rt=R\/2=2\\Omega\/2=1\\Omega;" "I=E\/Rt=8V\/1\\Omega=8A;"

Bulbs have the same resistance and connected parallel, so from Krichhoff's rule:

"I1+I2=I;"

"I1=I2;" "I1=I2=I\/2=8A\/2=4A;"

Also,

"U1=U2=RI1=2\\Omega*4A=8V;"

"P1=P2=I1U1=4A*8V=32W;"

"P=EI=8V*8A=64W."

Answer:

"I1=I2=4A;"

"U1=U2=8V;"

"P1=P2=32W;"

"P=64W."


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS