Answer to Question #347721 in Electric Circuits for Peter

Question #347721

An electric lamp rated 200w,240v operates for a time interval of 5 minutes calculate

(a)resistance of the lamp

(b)current flowing through the lamp

(c)electrical energy of the lamp


1
Expert's answer
2022-06-05T21:18:02-0400

Given:


"U=240V;\nP=200W;\nt=5min=300s."

Find:

a) R-resistance of lamp;

b) I- current flowing through the lamp;

c) E-electrical energy of the lamp.

Solution:

a) "P=UI=U^2\/R; R=P\/U^2;"

"R=200W\/(240V)^2=0.00347\\Omega=3.47 m\\Omega."

b) "I=P\/U=200W\/240V=0.833A."

c) "E=Pt=200W*300s=60000 J=60 kJ."

Answer:

a) "R=3.47 m\\Omega;"

b) "I=0.833 A;"

c) "E=60 kJ."


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