A robot probe lands on a new, uncharted planet. It has determined the diameter of the planet to be 8 * 10^6 m. It weighs a standard 1 kg mass and determines the 1 kg weighs only 5 newtons on this new planet.
1
Expert's answer
2012-10-10T07:38:18-0400
Dear visitor Unfortunately, the statement of your question is a bit confusing. What do you need to be done? Please, give us the details so we could help you
Learn more about our help with Assignments: Astronomy
Comments
Assignment Expert
04.12.13, 17:12
R = 8*10^6 m m = 1 kg P = 5 N Gravity law: P = mg = GM/R^2, where g is
the acceleration of the gravity, M is the mass of the planet,
G=6.67*10^-11 m^3/(kg*s^2) is the gravitational constant. Thus, g =
P/m = 5 m/s^2, M = gR^2/G = 4.8*10^24 kg. Average density is rho =
M/V, where V = 4/3*pi*R^3 is the volume of the planet. rho =
3g/(4*pi*G*R) = 2200 kg/m^2.
Rashad
04.12.13, 15:57
who can tell me the mass, acceleration of gravity,and avg. density in
this situation?
Leave a comment
Thank you! Your comments have been successfully added. However, they need to be checked by the moderator before being published.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
R = 8*10^6 m m = 1 kg P = 5 N Gravity law: P = mg = GM/R^2, where g is the acceleration of the gravity, M is the mass of the planet, G=6.67*10^-11 m^3/(kg*s^2) is the gravitational constant. Thus, g = P/m = 5 m/s^2, M = gR^2/G = 4.8*10^24 kg. Average density is rho = M/V, where V = 4/3*pi*R^3 is the volume of the planet. rho = 3g/(4*pi*G*R) = 2200 kg/m^2.
who can tell me the mass, acceleration of gravity,and avg. density in this situation?
Leave a comment