Answer to Question #48126 in Algebra for shivom

Question #48126
(cos2.cos3A - cos^2A.cos7A + cosA.cos10A)/(sin4A.sin3A - sin2A.sin5A + sin4A.sin7A) = cot6A.cot5A'
1
Expert's answer
2014-10-23T09:41:58-0400
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