In one experiment 76.2 gm of Fe are allowed to react with 86.7gm of S. which of the two is limiting reactant.. Fe(x) + S(p) FeS(p) ( Atomic Mass of S =32 a.m.u., Fe= 56 a.m.u.)
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Expert's answer
2013-04-17T09:34:41-0400
To calculate this, we need to calculate the amount of material of bothreagents n(Fe) = m / Ar n(Fe) = 76.2 gm/56 a.m.u. = 1.36 mol n(S) = m / Ar n(S) = 86.7gm/32 a.m.u. = 2.7 mol
Starting from the equation:
Fe(x) + S (p) ==> FeS (p)
Starting from the equation, it is seen that the sulfur in excess, thuslimiting reagent is iron.
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