Answer to Question #350890 in General Chemistry for DEBORAH

Question #350890

How many mL of 0.25M solution of H2SO4 will react with 10mL of 0.25M solution of NaOH?

1
Expert's answer
2022-06-16T04:23:04-0400

CM — concentration of molarity (mol/L)

V — volume (L)

n — amount of substance (mol)


CM (NaOH) = 0.25 M

V (NaOH) = 10 ml = 0.01 liters


"n(NaOH)=~C_M*~V =~ 0.25 * ~0.01 = ~0.0025 ~mol"


2NaOH + H2SO4 = Na2SO4 + 2H2O


2 mol NaOH — 1mol H2SO4

0.0025 mol NaOH — X


X = 0.0025*1/2= 0.00125 mol H2SO4




"V(H_2SO_4)=~\\cfrac {n}{C_M}= ~\\cfrac {0.00125}{0.25}=~ 0.005 L=~5~ml"




Answer: 5 ml



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