Two charged particles are 8.45cm apart. They are moved and the force on each of them is found to have trippled. How far are they now?
We can find the distance between two charged particles next way:
3F/F=(q1q2/x^2)/(q1q2/8.45^2)
3=8.45^2/x^2
x=8.45/sqrt(3)
Answer: 4.88 cm
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