Question #9615

give the starting value and constant multiplier for each sequence. then find the 7th term of the sequence. 27,18 ,12,...

Expert's answer

Give the starting value and constant multiplier for each sequence. then find the 7th term of the sequence. 27,18 ,12,

**Solution:**

This is geometric progression starting value equal to 27. So constant multiplier q equal to


q=a2a1=1827=13q = \frac {a _ {2}}{a _ {1}} = \frac {1 8}{2 7} = \frac {1}{3}


Formulae for the n-th term


an=a1qn1a _ {n} = a _ {1} q ^ {n - 1}


For 7th term of our sequence


a7=27(13)6=27729=127a _ {7} = 2 7 \left(\frac {1}{3}\right) ^ {6} = \frac {2 7}{7 2 9} = \frac {1}{2 7}


**Answer:**

starting value equal to 27;

constant multiplier q equal to 13\frac{1}{3} ;

7th term of sequence 127\frac{1}{27} ;

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