Question #9385

Sub 26
Ques. 22

Simplify:

2log3 6 - log3 4

Expert's answer

2log⁡36−log⁡34=2(log⁡(2)+log⁡(3))log⁡(3)−2log⁡(2)log⁡(3)=−log⁡(4)−2log⁡(6)log⁡(3)=log⁡(9)log⁡(3)=22 \log_ {3} 6 - \log_ {3} 4 = \frac {2 (\log (2) + \log (3))}{\log (3)} - \frac {2 \log (2)}{\log (3)} = - \frac {\log (4) - 2 \log (6)}{\log (3)} = \frac {\log (9)}{\log (3)} = 2

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