Question #6738
the perimeter of a rectangle is 68 cm. the length is 4 cm more than its width. find the dimensions of the rectangle
Expert's answer
Let's denote sides of the rectangle as a-length and b-width.
Then perimeter p=2a+2b=68
Also we know that a=b+4 hence
2a+2b=2(b+4)+2b=68
2b+8+2b=68
4b=60
b=15
and hence a=15+4=19
Then perimeter p=2a+2b=68
Also we know that a=b+4 hence
2a+2b=2(b+4)+2b=68
2b+8+2b=68
4b=60
b=15
and hence a=15+4=19
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#339914 on Dec 2023
#339914 on Dec 2023