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Lead(II) sulfate formed in the reaction of 145 mL of 0.123 M lead(II) nitrate and excess sodium sulfate.


c. Calculate the mass of lead(II) sulfate formed in the reaction



2. What is the concentration of an HNO3 solution if 25.0 ml reacts with 38.5 ml of 0.145 M K2PO4?



  Find the product of 101012 and 1012.  


If the mean and the standard deviation of a continuous random variable that is normally distributed are 19 and 5 respectively, what is the interval that contains 95% of the distribution? *

Solve the following equation using inverse method

[1 3 0] [x] [4]

[0 0.5 1] [y]=[1]

[0.5 0 1] [z] [3]


A spherical-shaped capacitor has a charge equivalent to 4.45 nanocoulombs when connected to a battery that has a voltage of 220 V. Suppose the two shells of the spherical capacitor are 5.34 centimeters apart, what are the capacitance and the radius of the inner sphere?

Calculate the potential difference of a battery connected to a capacitor consisting of two parallel plates with an area of 1.75 cm2 and a separation distance of 4.33 mm. Suppose that the charge present on the two plates is equal to 2.67 picocoulombs.

A cylindrical container has one end opened and the other end closed. It has a circular base of radius r cm. Given that the total surface area of the container is 200π cm2.


(a) Show that the volume of the container is V = 100πr - πr^3/2 cm3

(b) Find the maximum value of V.


  1. 0.315 moles of butane (C4H10) was burned in a copper calorimeter containing 4500 g of water. The calorimeter weighs 2,500 g. The temperature was observed to increase by 3.15 °C. Calculate the molar heat of combustion of butane (HEAT OF COMBUSTION PER MOLE). The specific heat of copper and water are 0.386 J/g. °C and 4.18 J/g. °C respectively.

Question 9

print("Original array:")

Answer: 

print(x)

>>>array([ 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])

print(“Remove even numbers from the array x: “)

Answer:

print(x)

>>>array([12, 14, 16, 18, 200])

print(“Replace all odd numbers in array x with -10:”)

Answer:

print(x)

>>> array([ 12, -10, 14, -10, 16, -10, 18, -10, 20])


Question 10

print("Original array:")

Answer: 

>>> print(X)

[10 12 14 16 18 20 22 24 26 28 30]

>>> print(Z)

[10 12 14 16 18 20 22 24 26 28 30]

Answer: 

>>> print(X)

[0 2 4 6 18 20 22 24 26 28 30]

Answer: 

>>> print(Z)

[10,12,14,16,-18,-20,-22,-24,26,28,30]


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