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Answer to Question #21502 in Mechanics | Relativity for Ameena
Question #21502
A horse and a dog are running with the same speed. If the weight of the horse is 10 times that of the dog, what is the ratio of their kinetic energy?
Expert's answer
Let the weight of a dog be m. Then the horse weight is 10m. If they are running with the same speed V, the kinetic energy of a dog is
K(dog) = mV²/2
and the kinetic energy of a horse is
K(horse) = 10mV²/2.
Therefore, the ratio of their kinetic energy is
R = K(dog)/K(horse) = (mV²/2) / (10mV²/2) = 0.1.
K(dog) = mV²/2
and the kinetic energy of a horse is
K(horse) = 10mV²/2.
Therefore, the ratio of their kinetic energy is
R = K(dog)/K(horse) = (mV²/2) / (10mV²/2) = 0.1.
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